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9x^2-71x=0
a = 9; b = -71; c = 0;
Δ = b2-4ac
Δ = -712-4·9·0
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5041}=71$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-71}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+71}{2*9}=\frac{142}{18} =7+8/9 $
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